Meduza Island

Antarctic island

65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472ArchipelagoWilhelm ArchipelagoArea11.9 ha (29 acres)Length670 m (2200 ft)Width434 m (1424 ft)AdministrationAdministered under the Antarctic Treaty SystemDemographicsPopulationuninhabited

Meduza Island (Bulgarian: остров Медуза, romanized: ostrov Meduza, IPA: [ˈɔstrof mɛˈduzɐ]) is the partly ice-covered island extending 670 m in southwest–northeast direction and 434 m in north–south direction in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 11.9 ha.[1]

The feature is so named because of its shape supposedly resembling a jellyfish ('meduza' in Bulgarian), and in association with other descriptive names of islands in the area.[1]

Location

Meduza Island is located at 65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472, which is 3.18 km southwest of Kosatka Island, 509 m west-northwest of Greblo Island, 2.33 km northwest of Rollet Island, 1.26 km east-northeast of Yastreb Island and 1.4 km southeast of Tyulen Island. British mapping in 2001.

Maps

  • British Admiralty Nautical Chart 446 Anvers Island to Renaud Island. Scale 1:150000. Admiralty, UK Hydrographic Office, 2001
  • Brabant Island to Argentine Islands. Scale 1:250000 topographic map. British Antarctic Survey, 2008
  • Antarctic Digital Database (ADD). Scale 1:250000 topographic map of Antarctica. Scientific Committee on Antarctic Research (SCAR). Since 1993, regularly upgraded and updated

See also

Notes

  1. ^ a b Meduza Island. SCAR Composite Gazetteer of Antarctica

References

  • Meduza Island. Adjusted Copernix satellite image

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.